Q. The differential equation of a particle executing SHM along $y$-axis is
A) $\frac{d^{2}y}{dt^{2}} + \omega^{2}y = 0$
B) $\frac{d^{2}y}{dt^{2}} + \omega^{2}y^{2} = 0$
C) $\frac{d^{2}y}{dt^{2}} - \omega^{2}y = 0$
D) $\frac{d^{2}y}{dt^{2}} + \omega y = 0$
Explanation
The correct answer is Option A: $\frac{d^{2}y}{dt^{2}} + \omega^{2}y = 0$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.