Q. $U$ is the PE of an oscillating particle and $F$ is the force acting on it at a given instant. Which of the following is true?
A) $\frac{U}{F} + x = 0$
B) $\frac{2U}{F} + x = 0$
C) $\frac{F}{U} + x = 0$
D) $\frac{F}{2U} + x = 0$
Explanation
(b) The potential energy, $U = \frac{1}{2}\ kx^{2}$
$2U = kx^{2}$
$2U = - Fx$ ($\because F = \ - kx$)
or $\frac{2U}{F} = - x$
or $\frac{2U}{F} + x = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.