Q. If $x,\ v\ and\ a$ denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period $T$, then, which of the following does not change with time?
A) $a^{2}T^{2} + 4\pi^{2}v^{2}$
B) $\frac{aT}{x}$
C) $aT + 2\pi v$
D) $\frac{aT}{v}$
Explanation
(b) $\frac{aT}{x} = \frac{\omega^{2}xT}{x} = \frac{4\pi^{2}}{T} \times T = \frac{4\pi^{2}}{T} =$ constant
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.