Q. An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is $15\ cm/s$ and the period is $628\ milli$-$seconds.$ The amplitude of the motion in centimeters is
A) 3.0
B) 2.0
C) 1.5
D) 1.0
Explanation
(c) $v_{\max} = a\omega = a\frac{2\pi}{T}$
$\Rightarrow a = \frac{v_{\max}T}{2\pi} = \frac{15 \times 628 \times 10^{- 3}}{2 \times 3.14} = 1.5\ cm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.