(b) When mass $700\ g$ is removed, the left out mass $(500 + 400)g$ oscillates with a period of $3\ s$
$\therefore 3 = t = 2\pi\sqrt{\frac{(500 + 400)}{k}}\ $ …(i)
When $500\ g$ mass is also removed, the left out mass is $400\ g$
$\therefore t^{'} = 2\pi\sqrt{\frac{400}{k}}\ \ \ \ \ \ $…(ii)
$\Rightarrow \frac{3}{t^{'}} = \sqrt{\frac{900}{400}} \Rightarrow t^{'} = 2s$