Q. What is time period of pendulum hanged in satellite? ($T$ is time period on earth)
A) Zero
B) $T$
C) Infinite
D) $\frac{T}{\sqrt{6}}$
Explanation
(c) Effective value of acceleration due to gravity is zero in the satellite, $ie$, $g_{eff} = 0$. Hence, time period of pendulum
$T = 2\pi\sqrt{\frac{l}{g_{eff}}} = 2\pi\sqrt{\frac{l}{0}} = \infty$
is infinite.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.