Q. If two springs $A$ and $B$ with spring constants 2 $k\ and\ k$, are stretched separately by same suspended weight, then the ratio between the work done in stretched $A$ and $B$ is

A) 1:2
B) 1:4
C) 1:3
D) 4:1
Explanation

(a) $mg = 2kx_{A}$
$mg = kx_{B}$
$\therefore$ $\frac{x_{A}}{x_{B}} = \frac{1}{2}$
$\therefore$ $W = Fx$
$\therefore$ $\frac{W_{A}}{W_{B}} = \frac{Fx_{A}}{Fx_{B}} = \frac{1}{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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