A particle is executing SHM with amplitude a. when the PE of a particle is one-fourth of its maximum value during the oscillation, its displacement from the equilibrium position will be

Question

Dr. Abubacker · Accepted Answer

(c) PE$= \frac{1}{2}m\omega^{2}y^{2} = \frac{1}{4} 	imes \frac{1}{2}m\omega^{2}a^{2}$
or $y^{2} = \frac{a^{2}}{4}$
or $y = \pm \frac{a}{2}$

Q. A particle is executing SHM with amplitude a. when the PE of a particle is one-fourth of its maximum value during the oscillation, its displacement from the equilibrium position will be

Explanation

Reviewed by Dr. Abubacker

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