Q. A particle of mass 200 g executes SHM. The restoring force is provided by a spring of force constant 80 N/m. The time period of oscillation is
A) 0.31 s
B) 0.15 s
C) 0.05 s
D) 0.02 s
Explanation
(a) $T = 2\pi\sqrt{\frac{m}{k}}$
$= 2\pi\sqrt{\frac{0.2}{80}} = 0.315$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.