Q. If a simple pendulum oscillates with an amplitude of 50 nm and time period of 2 s, then its maximum velocity is
A) $0.10\ ms^{- 1}$
B) $0.15\ ms^{- 1}$
C) $0.8\ ms^{- 1}$
D) $0.26\ ms^{- 1}$
Explanation
(b) $v_{\max} = a\omega = a \times \frac{2\pi}{T} = \left( 50 \times 10^{- 3} \right) \times \frac{2\pi}{2} = 0.15\ ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.