Q. If a body of mass $0.98\ kg$ is made to oscillate on a spring of force constant $4.84\ N/m,$ the angular frequency of the body is
A) $1.22\ rad/s$
B) $2.22\ rad/s$
C) $3.22\ rad/s$
D) $4.22\ rad/s$
Explanation
(b) $\omega = \sqrt{k/m} = \sqrt{\frac{4.84}{0.98}} = 2.22\ rad/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.