Q. Stationary waves of frequency $300\ Hz$ are formed in a medium in which the velocity of sound is $1200\ metre/sec.$ The distance between a node and the neighbouring antinode is
A) $1\ m$
B) $2\ m$
C) $3\ m$
D) $4\ m$
Explanation
(a) Required distance $= \frac{\lambda}{4} = \frac{v/n}{4} = \frac{1200}{4 \times 300} = 1\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.