Q. A tuning fork of frequency 500 Cycles/s is sounded on a resonance tube. The first and second resonance is obtained at 17 cm and 52 cm. the velocity of sound in $ms^{- 1}$ is

A) 175
B) 350
C) 525
D) 700
Explanation

(b) If the frequency of fork v, then speed of sound is given by
$v = 2v\left( l_{2} - l_{1} \right)$
Where$\ l_{1}$and$\ l_{2}$are length of air columns.
Given, v=500 cycles/s,
$l_{2} = 52cm = 52 \times 10^{- 2}m\ $
$l_{1} = 17cm = 17 \times 10^{- 2}m\ $
$\therefore v = 2 \times 500(52 - 17) \times 10^{- 2}$
$\Longrightarrow v = 350ms^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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