Q. The equation of a transverse wave is given by $y = 10\sin{\pi(0.01x - 2t)}$ Where $x$ and $y$ are in $cm$ and $t$ is in second. Its frequency is
A) $10{\ sec}^{- 1}$
B) $2\ {\ sec}^{- 1}$
C) $1\ {\ sec}^{- 1}$
D) $0.01{\ sec}^{- 1}$
Explanation
(c) Comparing with the standard equation,
$y = A\sin{\frac{2\pi}{\lambda}(vt - x)},$ we have
$v = 200\ cm/sec,\ \lambda = 200\ cm;\therefore n = \frac{v}{\lambda} = 1\ \sec^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.