Q. A pipe open at both the ends produce a note of fundamental frequency $v_{1}$ When the pipe is kept with $\frac{3}{4}$th of its length in water, it produces a note of fundamental frequency $v_{2}.$ The ration of $\frac{v_{1}}{v_{2}}$ is

A) $\frac{4}{3}$
B) $\frac{3}{4}$
C) 2
D) $\frac{1}{2}$
Explanation

(d) Accordingly
$v_{1} = \frac{v}{2l}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ldots(i)$
And
$v_{2} = \frac{v}{4l/4\ } = \frac{v}{l}\ \ \ \ \ \ \ldots(ii)$
Hence,
$\frac{v_{1}}{v_{2}} = \frac{1}{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Waves MCQs