(d) Accordingly $v_{1} = \frac{v}{2l}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ldots(i)$ And $v_{2} = \frac{v}{4l/4\ } = \frac{v}{l}\ \ \ \ \ \ \ldots(ii)$ Hence, $\frac{v_{1}}{v_{2}} = \frac{1}{2}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.