The equation of stationary wave along a stretched string is given by $y = 5\sin\frac{\pi x}{3}\cos{40\pi t}$ where $x$ and $y$ are in centimetre and $t$ in second. The separation between two adjacent nodes is :

Question

Dr. Abubacker · Accepted Answer

(c) Given $y = 5\sin\frac{\pi x}{3}\cos{40\pi t}$
Comparing with $y = 2a\cos\frac{2\pi vt}{\lambda}\sin\frac{2\pi x}{\lambda} \Rightarrow \lambda = 6\ cm$
$	herefore$ The separation between adjacent nodes $= \frac{\pi}{2} = 3\ cm$

Q. The equation of stationary wave along a stretched string is given by $y = 5\sin\frac{\pi x}{3}\cos{40\pi t}$ where $x$ and $y$ are in centimetre and $t$ in second. The separation between two adjacent nodes is :

Explanation

Reviewed by Dr. Abubacker

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