Q. A stretched string of length $l$fixed at both ends can sustain stationary waves of wavelength $\lambda$ given by
A) $\lambda = 2ln$
B) $\lambda = 2l/n\ $
C) $\lambda = l^{2}/2n$
D) $\lambda = n^{2}/2l$
Explanation
(b) Both the ends will behave as nodes. In the nth mode of vibration,
$n\left( \frac{\lambda}{2} \right) = l\ \ \therefore\ \lambda = \frac{2l}{n}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.