(b) $\frac{I_{\max}}{I_{\min}} = \left( \frac{\sqrt{\frac{I_{1}}{I_{2}}} + 1}{\frac{\sqrt{I_{1}}}{\sqrt{I_{2}}} - 1} \right)^{2} = \left( \frac{\sqrt{\frac{9}{4}} + 1}{\sqrt{\frac{9}{4}} - 2} \right)^{2} = \frac{25}{1}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.