Q. The velocity of waves in a string fixed at both ends is $2\ m/s.$ The string forms standing waves with nodes $5.0\ cm$ apart. The frequency of vibration of the string in $Hz$ is

A) 40
B) 30
C) 20
D) 10
Explanation

(c) Here $\frac{\lambda}{2} = 5.0\ cm\ \Rightarrow \lambda = 10\ cm$
Hence $n = \frac{v}{\lambda} = \frac{200}{10} = 20\ Hz$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Waves MCQs