When an engine passes near to a stationary observer then its apparent frequencies occurs in the ratio $5/3.$ If the velocity of engine is (Velocity of sound is $340\ m/s$)

Question

Dr. Abubacker · Accepted Answer

(c) When engine approaches towards observer
$n^{'} = n\left( \frac{v}{v - v_{S}} ight)$
When engine going away from observer
$n" = \left( \frac{v}{v + v_{S}} ight)n$
$	herefore\frac{n'}{n"} = \frac{v + v_{S}}{v - v_{S}} \Rightarrow \frac{5}{3} = \frac{340 + v_{S}}{340 - v_{S}} \Rightarrow v_{S} = 85\ m/s$

Q. When an engine passes near to a stationary observer then its apparent frequencies occurs in the ratio $5/3.$ If the velocity of engine is (Velocity of sound is $340\ m/s$)

Explanation

Reviewed by Dr. Abubacker

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