Q. An open pipe is suddenly closed at one end with the result that the frequency of third harmonic of the closed pipe is found to be higher at 100 Hz. The fundamental frequency of the open pipe is

A) 200 Hz
B) 480 Hz
C) 240 Hz
D) 300 Hz
Explanation

(a) Frequency of third harmonic of closed pipe
$n_{1} = \frac{3v}{4l}$
Fundamental frequency of open pipe
$n_{2} = \frac{2}{2l}$
As $n_{1} - n_{2} = 100$
$\frac{v}{4l} = 100$
$\therefore\ \frac{v}{2l} = 200\ Hz$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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