Q.
A wave travelling in positive $X$-direction with $A = 0.2m$ has a velocity of $360\ m/sec.$ If $\lambda = 60m,$ then correct expression for the wave is
A) $y = 0.2\sin\left\lbrack 2\pi\left( 6t + \frac{x}{60} \right) \right\rbrack$
B) $y = 0.2\sin\left\lbrack \pi\left( 6t + \frac{x}{60} \right) \right\rbrack$
C) $y = 0.2\sin\left\lbrack 2\pi\left( 6t - \frac{x}{60} \right) \right\rbrack$
(c) A wave travelling in positive $x$-direction may be represented as $y = A\sin{\frac{2\pi}{\lambda}(vt - x)}.$ On putting values $y = 0.2\sin{\frac{2\pi}{60}(360t - x) \Rightarrow y = 0.2\sin{2\pi\left( 6t - \frac{x}{60} \right)}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.