Q. If the length of a closed organ pipe is $1.5\ m$ and velocity of sound is $330\ m/s,$ then the frequency for the second note is
A) $220\ Hz$
B) $165\ Hz$
C) $110\ Hz$
D) $55\ Hz$
Explanation
(b) For closed pipe second note $= \frac{3v}{4l} = \frac{3 \times 330}{4 \times 1.5} = 165\ Hz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.