Q. If the phase difference between two sound waves of wavelength $\lambda$ is $60^{o},$ the corresponding path difference is
A) $\frac{\lambda}{6}$
B) $\frac{\lambda}{2}$
C) $2\lambda$
D) $\frac{\lambda}{4}$
Explanation
(a) Path difference for a given phase difference $\delta$ is given by
$\mathrm{\Delta}x = \frac{\lambda}{2\pi}\delta$
Given that $\delta = 60{^\circ} = \frac{\pi}{3}$
$\Delta x = \frac{\lambda}{2\pi} \times \frac{\pi}{3}\ \therefore\mathrm{\Delta}x = \frac{\lambda}{6}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.