(a) Given that y=15sin (660 πt—0.02πx)
Comparing with general equation of progressive wave, we get
$y = (x,t) = a\sin\left( \frac{2\pi}{T}t - \frac{2\pi}{\lambda}x \right)$
$\therefore\frac{2\pi}{T} = 660\pi\ $
$or\ \ \frac{1}{T} = 330\ \ \ \ \ or\ \ \ v = 330\ Hz$