Q. The equation of a progressive wave can be given by y=15 sin (660$\ \pi t$-0.02$\ \pi x$) cm. the frequency of the wave is

A) 330 Hz
B) 342 Hz
C) 365 Hz
D) 660 Hz
Explanation

(a) Given that y=15sin (660 πt—0.02πx)
Comparing with general equation of progressive wave, we get
$y = (x,t) = a\sin\left( \frac{2\pi}{T}t - \frac{2\pi}{\lambda}x \right)$
$\therefore\frac{2\pi}{T} = 660\pi\ $
$or\ \ \frac{1}{T} = 330\ \ \ \ \ or\ \ \ v = 330\ Hz$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Waves MCQs