Q. The number of beats produced per second by two vibrations: $x_{1} = x_{0}\sin{646\ \pi t}$ and $x_{2} = x_{0}\sin 652\pi t$ is
A) 2
B) 3
C) 4
D) 6
Explanation
(b) From the given equation $\omega_{1} = 2\pi n_{1} = 646\pi \Rightarrow n_{1} = 323$
And $\omega_{2} = 2\pi n_{2} = 652\pi \Rightarrow n_{2} = 326$
Hence, beat frequency $= 326 - 323 = 3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.