(b) Let $\mathrm{\Delta}l$be the end correction. Given that,
Fundamental tone for a length 0.1m=first overtone for the length 0.35m
$\therefore\frac{v}{4(0.1 + \mathrm{\Delta}l)} = \frac{3v}{4(0.35 + \mathrm{\Delta}l)}$
Solving this equations we get $\mathrm{\Delta}l$=0.025m=2.5 cm