Q. While measuring the speed of sound by performing a resonance column experiment, a student gets the first resonance condition at a column length of 18 cm during winter. Repeating the same experiment during summer, she measures the column length to be x cm for the second resonance. Then
A) 18 >x
B) X >54
C) 54 > x >36
D) 36 > x > 18
Explanation
(b) Here, $\iota_{1} = 18\ cm\ $
$f = \frac{v_{1}}{4\iota_{1}}$
$f = \frac{3v_{2}}{4\iota_{2}},$
$where\ \iota_{2} = x$ According to given situation and also $v_{1} < v_{2}$as during summer temperature would be higher.
$\frac{3v_{2}}{4\iota_{2}} = \frac{v_{\iota}}{4\iota_{1}}\ $
$\Longrightarrow \ \ \ \ \ \ x = 54 \times (A\ quantity\ greater\ than\ I)$
So, x>54
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.