A sound absorber the sound level by 20 dB. The intensity decreases by a factor of

Question

Dr. Abubacker · Accepted Answer

(d) Let intensity of sound be I and I’.
Loudness of sound initially
$\beta_{1} = 10\log\left( \frac{I}{I_{0}} ight)$
Later,
$\beta_{2} = 10\log\left( \frac{I^{'}}{I_{0}} ight)$
Given, $\beta_{2} - \beta_{1} = 20$
$	herefore 20 = \log\left( \frac{I^{'}}{I} ight)\ $
$I^{'} = 100I$

Q. A sound absorber the sound level by 20 dB. The intensity decreases by a factor of

Explanation

Reviewed by Dr. Abubacker

Want more practice?