Two string A and B are slightly out tune and produces beats of frequency 5Hz. Increasing the tension in B reduces the beat frequency to 3Hz. If the frequency of string A is 450 Hz, calculate the frequency of string B.

Question

Dr. Abubacker · Accepted Answer

(c) $n_{A}$=unknown frequency=450 Hz, $n_{B} = ?x = 5\ Hz$ which is decreasing after tension is increased (i.e., x$\downarrow$)
Hence, $n_{A} \downarrow - n_{B} = x \downarrow \ \ \ \ \ \ \ldots.(i)correct$
$n_{B} - n_{A} \downarrow = x \downarrow \ \ \ \ldots\ldots.(ii)wrong$
$\Longrightarrow n_{B} = n_{A} - x = 450 - 5 = 445\ Hz$

Q. Two string A and B are slightly out tune and produces beats of frequency 5Hz. Increasing the tension in B reduces the beat frequency to 3Hz. If the frequency of string A is 450 Hz, calculate the frequency of string B.

Explanation

Reviewed by Dr. Abubacker

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