The wavelength of two notes in air are $\frac{36}{195}$ m and $\frac{36}{193}$m. each note produces 10 beats per second separately with a third note of fixed frequency. The velocity of sound in air in m/s is

Question

Dr. Abubacker · Accepted Answer

(d) Beat frequency=$v_{1}\sim v_{2}$
Let the frequency of third note be n.
Then,
$\frac{195v}{36} - v = 10\ \ \ldots(i)$
And
$v - \frac{193v}{36} = 10\ \ldots(ii)$
Adding Eqs. (i) and (ii)
$\frac{v}{18} = 20$
$\Longrightarrow \ \ v = 360\ ms^{- 1}$

Q. The wavelength of two notes in air are $\frac{36}{195}$ m and $\frac{36}{193}$m. each note produces 10 beats per second separately with a third note of fixed frequency. The velocity of sound in air in m/s is

Explanation

Reviewed by Dr. Abubacker

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