(b) As $\frac{l_{2}}{2l} = \frac{l_{2}^{'}}{l_{1}^{'}}$ $\therefore\frac{60}{40} = \frac{l_{2}^{'}}{50^{'}}$ , $l_{2}^{'} = \frac{50 \times 60}{40} = 75\ cm$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.