Q. Ten tuning fork are arranged in increasing order of frequency in such a way that any two nearest tuning forks produce 4 beats $s^{- 1}$. The highest frequency is twice that of the lowest. Possible highest and lowest frequencies are
A) 80 and 40
B) 100 and 50
C) 44 and 32
D) 72 and 36
Explanation
(d) In $n$ is frequency of first fork, then frequency of the last (10th fork)$= n + 4(10 - 1) = 2\ n$
$\therefore n = 36\ and\ 2\ n = 72$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.