Q. In an experiment with sonameter a tuning fork of frequency 256 Hz resonates with a length of 25 cm and another tuning fork resonates with a length of 16 cm. tension of the string remaining constant the frequency of the second tuning fork is

A) 163.84 Hz
B) 400 Hz
C) 320 Hz
D) 204.8 Hz
Explanation

(b) For sonometer
$v \propto \frac{1}{l}$
$\therefore\ \frac{v_{1}}{v_{2}} = \frac{l_{2}}{l_{1}} \Longrightarrow \frac{256}{v_{2}} = \frac{16}{25}\ $
$v_{2} = \frac{256 \times 25}{16} = 400\ Hz$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Waves MCQs