The relation between time and displacement for two particles is given by $y_{1} = 0.06\sin{2\pi\left( 0.04t + \phi_{1} \right),}y_{2} = 0.03\sin{2\pi(1.04t + \phi_{2})}$ The ratio of the intensity of the waves produced by the vibrations of the two particles will be

Question

Dr. Abubacker · Accepted Answer

(c) $\frac{I_{1}}{I_{2}} = \frac{a_{1}^{2}}{a_{2}^{2}} = \left( \frac{0.06}{0.03} \right)^{2} = \frac{4}{1}$

Q. The relation between time and displacement for two particles is given by $y_{1} = 0.06\sin{2\pi\left( 0.04t + \phi_{1} \right),}y_{2} = 0.03\sin{2\pi(1.04t + \phi_{2})}$ The ratio of the intensity of the waves produced by the vibrations of the two particles will be

Explanation

Reviewed by Dr. Abubacker

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