Q. If v is the speed of sound in air then the shortest length of the closed pipe which resonates to a frequency v, is
A) $\frac{v}{2v}$
B) $\frac{v}{4v}$
C) $\frac{4v}{v}$
D) $\frac{2v}{v}$
Explanation
(b) In close organ pipe
$v = \frac{v}{4l}$
So,
$l = \frac{v}{4v}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.