Q. The equation of stationary wave along a stretched string is given by $y = 5\sin\frac{\pi x}{3}\cos{40\pi t,}$ where $x$ and $y$ are in cm and $t$ in second. The separation between two adjacent nodes is

A) $1.5\ cm$
B) $3\ cm$
C) $6\ cm$
D) $4\ cm$
Explanation

(b) On comparing the given equation with standard equation
$y = 2a\sin\frac{2\pi x}{\lambda}\cos{\frac{2\pi vt}{\lambda} \Rightarrow \frac{2\pi x}{\lambda}} = \frac{\pi x}{3} \Rightarrow \lambda = 6$
Separation between two adjacent nodes $= \frac{\lambda}{2} = 3\ cm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Waves MCQs