(d) The perceived frequency $\left( f^{'} \right)$ is related to the actual frequency $\left( f_{o} \right)$ and the relative speeds of the source $\left( v_{s} \right)$ and observer $\left( v_{o} \right)$ of waves in the medium is given by
$f^{'} = f_{o}\left( \frac{v + v_{o}}{v - v_{s}} \right)$
Given,
v=340m/s $v_{o} = 15$m/s, $v_{s} = 20$m/s
$\therefore f^{'} = 600 \times \left( \frac{340 + 15}{340 - 20} \right)$
$= \frac{355}{320} \times 600 = 666Hz$