A source producing sound of frequency $170\ Hz$ is approaching a stationary observer with a velocity $17\ ms^{- 1}.$ The apparent change in the wavelength of sound heard by the observer is (speed of sound in air $= 340\ ms^{- 1}$)

Question

Dr. Abubacker · Accepted Answer

(a) $\lambda = \frac{v}{n} = \frac{340}{170} = 2m,\ n^{'} = \frac{340}{340 - 17} 	imes 170 \Rightarrow n^{'} = 178.9Hz$
Now $\lambda^{'} = \frac{v}{n'} = \frac{340}{178.9} = 1.9$
$\Rightarrow \lambda - \lambda^{'} = 2 - 1.9 = 0.1$

Q. A source producing sound of frequency $170\ Hz$ is approaching a stationary observer with a velocity $17\ ms^{- 1}.$ The apparent change in the wavelength of sound heard by the observer is (speed of sound in air $= 340\ ms^{- 1}$)

Explanation

Reviewed by Dr. Abubacker

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