A motor cycle starts from rest and accelerates along a straight path at $2\ ms^{- 2}$. At the starting point of the motor cycle gone when the driver hears the frequency of the siren at 94% of its value when the motor cycle was rest? (Speed =330 $ms^{- 1}$)

Question

Dr. Abubacker · Accepted Answer

(b) Motor cycle, u=0, $a = 2ms^{- 2}$
Observe is in motion and source is at rest
$\Longrightarrow \ \ \ \ n^{'} = n\frac{v - v_{2}}{v + v_{s}}$
$\Longrightarrow \frac{94}{100}n = n\frac{330 - v_{o}}{330}$
$\Longrightarrow 330 - v_{o} = \frac{330 	imes 94}{100}$
$\Longrightarrow v_{o} = 330 - \frac{94 	imes 33}{10} = \frac{33 	imes 6}{10}ms^{- 1}$
$s = \frac{v^{2} - u^{2}}{2a} = \frac{9 	imes 33 	imes 33}{100}$
$= \frac{9 	imes 1089}{100} = 98m.$

Q. A motor cycle starts from rest and accelerates along a straight path at $2\ ms^{- 2}$. At the starting point of the motor cycle gone when the driver hears the frequency of the siren at 94% of its value when the motor cycle was rest? (Speed =330 $ms^{- 1}$)

Explanation

Reviewed by Dr. Abubacker

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