Q. Four wires of identical length, diameters and of the same material are stretched on a sonometre wire. If the ratio of their tensions is 1 : 4 : 9 : 16 then the ratio of their fundamental frequencies are
A) 16 : 9 : 4 : 1
B) 4 : 3 : 2 : 1
C) 1 : 4 : 2 : 16
D) 1 : 2 : 3 : 4
Explanation
(d) $n \propto \sqrt{T}$
$\Rightarrow n_{1}:n_{2}:n_{3}:n_{4} = \sqrt{1}\ :\sqrt{4}\ :\sqrt{9}\ :\sqrt{16} = 1\ :2\ :3\ :4$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.