Q. Velocity of sound waves in air is $330ms^{- 1}$. For a particular sound in air, a path difference of 40cm is equivalent to a phase difference of $1.6\pi$.The frequency of the wave is

A) 165 Hz
B) 150 Hz
C) 660 Hz
D) 330 Hz
Explanation

(c) Here, $v = 330\ ms^{- 1}$
Phase difference of $1.6\pi = 40\ cm$
Phase difference of $2\pi = \frac{40}{1.6\pi} \times 2\pi\ cm = 50\ cm$
ie, $\lambda = 50\ cm = 0.5\ cm$
$n = \frac{v}{\lambda} = \frac{330}{0.5} = 660\ Hz$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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