Q. The time of reverberation of a room $A$ is one second. What will be the time (in seconds) of reverberation of a room, having all the dimensions double of those of room $A$
A) $\frac{1}{2}$
B) $1$
C) 2
D) 4
Explanation
(c) Reverberation time, $T = \frac{0.61V}{aS}$
$\Rightarrow \frac{T_{1}}{T_{2}} = \left( \frac{V_{1}}{V_{2}} \right)\left( \frac{S_{2}}{S_{1}} \right) = \left( \frac{V}{8V} \right)\left( \frac{4S}{S} \right) = \frac{1}{2}$
$\Rightarrow T_{2} = 2T_{1} = 2 \times 1 = 2\ \sec.\ \lbrack\because T_{1} = 1\ \sec\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.