(b) Apparent frequency in this case $n^{'} = \frac{n(v + v_{o})}{v}$ $\because\frac{v + v_{o}}{v} > 1 \Rightarrow \frac{n^{'}}{n} > i.e.\ n^{'} > n$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.