Q. How many times more intense is a 60 dB sound than a dB sound?

A) 1000
B) 2
C) 100
D) 4
Explanation

(a) Loudness, $L = 10\log_{10}\frac{I}{I_{0}}$
$60 = 10\log_{10}\frac{I_{1}}{I_{0}}$
$\Longrightarrow \frac{I_{1}}{I_{0}} = 10^{6}\ \ \ \ \ \ldots(i)$
$similarly,\ \ \ \ \ 30 = 10\ lig_{10}\frac{I_{2}}{I_{0}}$
$\frac{I_{2}}{I_{0}} = 10^{3}\ \ \ldots(ii)$
Dividing Eq. (i) by Eq. (ii), we get
$\frac{I_{1}}{I_{2}} = 1000$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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