Q. A man fires a bullet standing between two cliffs. First echo is heard after 3 seconds and second echo is heard after 5 seconds. If the velocity of sound is $330\ m/s,$ then the distance between the cliffs is
A) $1650\ m$
B) $1320\ m$
C) $990\ m$
D) $660\ m$
Explanation
(b) [image:15_image59.png]
$2\left( d_{1} + d_{2} \right) = v\left( t_{1} + t_{2} \right) \Rightarrow d_{1} + d_{2} = \frac{330 \times (3 + 5)}{2} = 1320\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.