A cylindrical tube open at both the ends has a fundamental frequency of 390 Hz in air. If $\frac{1}{4}$of the tube is immersed vertically in water the fundamental frequency of air column is

Question

Dr. Abubacker · Accepted Answer

(a) Fundamental frequency of cylindrical open tube
$n = \frac{v}{2L} = 390\ Hz$
When it is immersed in water it become a closed tube of length
$\frac{3}{4}^{th}$ of the initial length.
Therefore, its fundamental frequency is
$n^{'} = \frac{v}{4\left( \frac{3}{4}L ight)} = \frac{v}{3L} = \frac{2}{3}\left( \frac{v}{2L} ight)$
$= \frac{2}{3} 	imes 390Hz = 260Hz$

Q. A cylindrical tube open at both the ends has a fundamental frequency of 390 Hz in air. If $\frac{1}{4}$of the tube is immersed vertically in water the fundamental frequency of air column is

Explanation

Reviewed by Dr. Abubacker

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