(b) Compare the given equation with the standard form of stationary wave equation
$y = 2r\sin\frac{2\pi x}{\lambda}\cos\frac{2\pi vt}{\lambda}$,
We get $\frac{2\pi x}{\lambda} = \frac{2\pi vt}{3}\ \ \ \ \therefore\ \lambda = 3cm$
Separation between two adjacent nodes $= \frac{\lambda}{2} = 1.5cm$