Q. The equation of a stationary wave along a stretched string is given by $y = 4\sin{\frac{2\pi x}{2}\ \cos 40\pi t}$ where x and y are in cms and $t$ is in sec. The separation between two adjacent nodes is

A) 3 cm
B) 1.5 cm
C) 6 cm
D) 4 cm
Explanation

(b) Compare the given equation with the standard form of stationary wave equation
$y = 2r\sin\frac{2\pi x}{\lambda}\cos\frac{2\pi vt}{\lambda}$,
We get $\frac{2\pi x}{\lambda} = \frac{2\pi vt}{3}\ \ \ \ \therefore\ \lambda = 3cm$
Separation between two adjacent nodes $= \frac{\lambda}{2} = 1.5cm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Waves MCQs