Q. Two waves having the intensities in the ratio of 9 : 1 produce interference. The ratio of maximum to the minimum intensity, is equal to
A) 2 : 1
B) 4 : 1
C) 9 : 1
D) 10 : 8
Explanation
(b) $\frac{I_{\max}}{I_{\min}} = \frac{\left( \frac{\sqrt{I_{1}}}{\sqrt{I_{2}}} + 1 \right)^{2}}{\left( \frac{\sqrt{I_{1}}}{\sqrt{I_{2}}} - 1 \right)^{2}} = \frac{\left( \sqrt{\frac{9}{1}} + 1 \right)^{2}}{\left( \sqrt{\frac{9}{1}} - 1 \right)^{2}} = \frac{4}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.