Q. If $v$ is the speed of sound in air then the shortest length of the closed pipe which resonates to a frequency $n$
A) $\frac{v}{4n}$
B) $\frac{v}{2n}$
C) $\frac{2n}{v}$
D) $\frac{4n}{v}$
Explanation
(a) For shortest length of pipe mode of vibration must be fundamental
$i.e.,\ n = \frac{v}{4l} \Rightarrow l = \frac{v}{4n}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.